Math  /  Calculus

QuestionUsing Linear equation with constant coefficient form:
1. d2ydx2dydx=0\frac{d^2y}{dx^2} - \frac{dy}{dx} = 0
2. 2d2ydx2+dydx=02\frac{d^2y}{dx^2} + \frac{dy}{dx} = 0
3. d2ydx24y=0\frac{d^2y}{dx^2} - 4y = 0
4. d2ydx2dydy2y=0\frac{d^2y}{dx^2} - \frac{dy}{dy} - 2y = 0

Studdy Solution
Write the general solution for the fourth equation:
y(x)=C1e2x+C2ex y(x) = C_1 e^{2x} + C_2 e^{-x}

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord