QuestionWhat are the first three terms of the arithmetic sequence $a_{n}=-4-7(n-1)$ ? $$\begin{array}{l} a_{1}=\text { Ex:10 } 0 \\ a_{2}=\square \\ a_{3}=\square \end{array}$$

Studdy Solution
Calculate the third term $a_3$.
Substitute $n = 3$ into the formula:
$$a_3 = -4 - 7(3-1)$$
Simplify:
$$a_3 = -4 - 7 \times 2$$ $$a_3 = -4 - 14$$ $$a_3 = -18$$
The first three terms of the arithmetic sequence are:
$$a_1 = -4, \quad a_2 = -11, \quad a_3 = -18$$