QuestionWhat are the roots of the following polynomial: $x^{3}-9 x$ ? $x=0,3$ $x=3$ 的 $x=-3,0$ $x=-3,0,3$ $x=-3,3$

Studdy Solution
Solve the equation $x(x - 3)(x + 3) = 0$ for its roots.
Set each factor equal to zero:
1. $x = 0$
2. $x - 3 = 0$ which gives $x = 3$
3. $x + 3 = 0$ which gives $x = -3$
The roots of the polynomial $x^3 - 9x$ are:
$$\boxed{-3, 0, 3}$$