Math  /  Geometry

QuestionWhat is the area of a triangle with vertices at (4,1),(7,5)(-4,1),(-7,5), and (0,1)(0,1) ?

Studdy Solution
Calculate the area using the substituted values:
=12(4)(4)+(7)(0)+(0)(4)= \frac{1}{2} \left| (-4)(4) + (-7)(0) + (0)(-4) \right| =1216+0+0= \frac{1}{2} \left| -16 + 0 + 0 \right| =12×16= \frac{1}{2} \times 16 =8= 8
The area of the triangle is:
8 \boxed{8}

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