Math  /  Data

QuestionFind the average velocity of an object from 2t42 \leq t \leq 4 and from 1t51 \leq t \leq 5 using y=s(t)y=s(t) data.

Studdy Solution
Calculate the average velocity over the interval 1t51 \leq t \leq5.
AV[1,5]=183551=4.25meters/minuteAV_{[1,5]} = \frac{18 -35}{5 -1} = -4.25 \, \text{meters/minute}The average velocity of the object over the interval 2t42 \leq t \leq4 is 77 meters/minute and over the interval 1t51 \leq t \leq5 is 4.25-4.25 meters/minute. The negative sign indicates that the object is moving downwards.

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