Math  /  Measurement

Question Solve for aa in b=c+aca2b=\frac{c+a c}{a-2}. The rearranged equation is a=c+bcb2a=\frac{c+b c}{b-2}.

Studdy Solution
Rearrange the terms in the denominator to match the conventional order.
a=c+2bbc a = \frac{c + 2b}{b - c}
Now we see that our derived equation matches one of the provided options after factoring out the negative sign from the denominator.
The rearranged equation for a a in b=c+aca2 b = \frac{c + ac}{a - 2} is:
a=c+2bbc a = \frac{c + 2b}{b - c}
This matches the first option provided:
a=c+2bbc a = \frac{c + 2b}{b - c}

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