Math  /  Calculus

QuestionWhat is the first derivative of p(x)=ln(4x3+x2+1)p(x)=\ln \left(4 x^{3}+x^{2}+1\right) ?
Select the correct answer below: 12x2+2x4x3+x2+1\frac{12 x^{2}+2 x}{4 x^{3}+x^{2}+1} 4x3+x2+112x2+2x\frac{4 x^{3}+x^{2}+1}{12 x^{2}+2 x} 14x3+x2+1\frac{1}{4 x^{3}+x^{2}+1} ln(12x2+2x)\ln \left(12 x^{2}+2 x\right) 12x2+2xln(4x3+x2+1)\frac{12 x^{2}+2 x}{\ln \left(4 x^{3}+x^{2}+1\right)}

Studdy Solution
Compare the simplified derivative to the given options. The correct answer is:
12x2+2x4x3+x2+1 \frac{12x^2 + 2x}{4x^3 + x^2 + 1}
The correct answer is:
12x2+2x4x3+x2+1 \boxed{\frac{12x^2 + 2x}{4x^3 + x^2 + 1}}

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