Math  /  Algebra

QuestionWhat is the slope of a line that is perpendicular to the line whose equation is Ax+By+C=0,A0A x+B y+C=0, A \neq 0 and B0B \neq 0 ?
The slope of the line perpendicular to the line Ax+By+C=0A x+B y+C=0 is \square

Studdy Solution
The slope of the line perpendicular to Ax+By+C=0Ax + By + C = 0 is BA\frac{B}{A}.

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