Math  /  Algebra

Question2 3 4 5 6 7 8 9 10
What is the solution set of the quadratic inequality 6x2+106 x^{2}+1 \leq 0 ? {xxR}\{x \mid x \in \mathbb{R}\} {xx=16}\left\{x \left\lvert\, x=-\frac{1}{6}\right.\right\} \varnothing {xx=16}\left\{x \left\lvert\, x=\frac{1}{6}\right.\right\} Mark this and return Save and Exit Next Submit

Studdy Solution
Conclude that there are no real values of x x that satisfy the inequality 6x2+10 6x^2 + 1 \leq 0 . Therefore, the solution set is empty.
The solution set is:
\varnothing

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord