QuestionWhen converting $1.50 \mathrm{~kg} / \mathrm{L}$ into $\mathrm{g} / \mathrm{mL}$, what are the two missing steps needed to complete the calculation? $\frac{1.50 \mathrm{~kg}}{L} \times \frac{?}{?} \times \frac{?}{?}$ $\frac{1000 \mathrm{~g}}{1 \mathrm{Kg}}$ $\frac{1 L}{1000 \mathrm{~mL} L}$ $\frac{1 \mathrm{~mL}}{1000 \mathrm{~L}}$ $\frac{1000 \mathrm{~kg}}{1 \mathrm{~g}}$ $\frac{1 \mathrm{~g}}{1000 \mathrm{~kg}}$ $\frac{1000 L}{1 m L}$

Studdy Solution
Apply the conversion factors to complete the calculation.
Given:
$\frac{1.50 \mathrm{~kg}}{\mathrm{L}} \times \frac{1000 \mathrm{~g}}{1 \mathrm{~kg}} \times \frac{1 \mathrm{~L}}{1000 \mathrm{~mL}}$
Simplify the expression:
$\frac{1.50 \times 1000 \mathrm{~g}}{1 \times 1000 \mathrm{~mL}} = \frac{1500 \mathrm{~g}}{1000 \mathrm{~mL}} = 1.50 \mathrm{~g/mL}$
The two missing steps needed to complete the calculation are:
1. $\frac{1000 \mathrm{~g}}{1 \mathrm{~kg}}$
2. $\frac{1 \mathrm{~L}}{1000 \mathrm{~mL}}$