Math  /  Data & Statistics

QuestionWhen it rains, water vapor in the air condenses into liquid water, and energy is released. (a) How much energy is released when 0.0479 m ( 1.89 inch) of rain falls over an area of 2.59×106 m22.59 \times 10^{6} \mathrm{~m}^{2} (one square mile)? (b) If the average energy needed to heat one home for a year is 1.50×1011 J1.50 \times 10^{11} \mathrm{~J}, how many homes could be heated for a year with the energy

Studdy Solution
Calculate the number of homes that can be heated using the formula:
Number of homes=Total energyEnergy per home \text{Number of homes} = \frac{\text{Total energy}}{\text{Energy per home}}
Number of homes=2.8070336×1014J1.50×1011J/home1871homes \text{Number of homes} = \frac{2.8070336 \times 10^{14} \, \text{J}}{1.50 \times 10^{11} \, \text{J/home}} \approx 1871 \, \text{homes}
The energy released can heat approximately 1871 1871 homes for a year.

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