QuestionWhich equation shows a valid step in solving $\sqrt[3]{2 x-6}+\sqrt[3]{2 x+6}=0$ ? $(\sqrt[3]{2 x-6})^{2}=(\sqrt[3]{2 x+6})^{2}$ $(\sqrt[3]{2 x-6})^{2}=(-\sqrt[3]{2 x+6})^{2}$ $(\sqrt[3]{2 x-6})^{3}=(\sqrt[3]{2 x+6})^{3}$ $(\sqrt[3]{2 x-6})^{3}=(-\sqrt[3]{2 x+6})^{3}$ Mark this and return sessmentViewer/Activit...

Studdy Solution
To eliminate the cube roots, we cube both sides of the equation: $(\sqrt[3]{2x-6})^3 = (-\sqrt[3]{2x+6})^3$
The valid algebraic step is:
\[ (\sqrt[3]{2x-6})^3 = (-\sqrt[3]{2x+6})^3 $

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