QuestionWhich of the following statements are FALSE? $2 \in A \cup B$ implies that if $2 \notin A$ then $2 \in B$ $\{3\} \subseteq A-B$ and $\{2\} \subseteq B$ implies that $\{2,3\} \subseteq A \cup B$. $\{2,3\} \subseteq A$ implies that $2 \in A$ and $3 \in A$. $A \cap B \supseteq\{2,3\}$ implies that $\{2,3\} \subseteq A$ and $\{2,3\} \subseteq B$. $\{2\} \in A$ and $\{3\} \in A$ implies that $\{2,3\} \subseteq A$.

Studdy Solution
Analyze the statement: $\{2\} \in A$ and $\{3\} \in A$ implies that $\{2,3\} \subseteq A$.
- $\{2\} \in A$ means the set containing $2$ is an element of $A$, not that $2$ itself is an element of $A$. - Similarly, $\{3\} \in A$ means the set containing $3$ is an element of $A$. - This does not imply that $2$ and $3$ themselves are elements of $A$. - This statement is FALSE.
The FALSE statement is: $\{2\} \in A$ and $\{3\} \in A$ implies that $\{2,3\} \subseteq A$.