Math  /  Geometry

QuestionWhich would prove that ABCXYZ\triangle A B C-\triangle X Y Z ? Select two options. BAYX=BCYZ=ACXZ\frac{B A}{Y X}=\frac{B C}{Y Z}=\frac{A C}{X Z} BAYX=BCYZ,CZ\frac{B A}{Y X}=\frac{B C}{Y Z}, \angle C \geq \angle Z ACxz=BAyx,Ax\frac{A C}{x z}=\frac{B A}{y x}, \angle A \cong \angle x BAYX=ACYZ=BCXZ\frac{B A}{Y X}=\frac{A C}{Y Z}=\frac{B C}{X Z} BCXY=BAZX,CX\frac{B C}{X Y}=\frac{B A}{Z X}, \angle C \approx \angle X

Studdy Solution
Identify the options that satisfy the similarity criteria:
- Option 1: SSS Similarity - Option 3: SAS Similarity
The options that prove ABCXYZ\triangle ABC \sim \triangle XYZ are:
1. BAYX=BCYZ=ACXZ\frac{BA}{YX} = \frac{BC}{YZ} = \frac{AC}{XZ}
2. ACXZ=BAYX,AX\frac{AC}{XZ} = \frac{BA}{YX}, \angle A \cong \angle X

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