Math  /  Algebra

Questionwith David's rope. 5.2 Newton's First Law
22. Two forces of F1=75.02(i^j^)N\vec{F}_{1}=75.02(\hat{i}-\hat{j}) \mathrm{N} and F2=150.02(i^j^)N\vec{F}_{2}=\frac{150.0}{\sqrt{2}}(\hat{i}-\hat{j}) \mathrm{N} act on an object. Find the third force F3\vec{F}_{3} that is needed to balance the first two forces.

Studdy Solution
Determine the third force needed to balance the resultant force.
The third force F3\vec{F}_{3} must be equal in magnitude but opposite in direction to Fresultant\vec{F}_{\text{resultant}} to achieve equilibrium:
F3=Fresultant\vec{F}_{3} = -\vec{F}_{\text{resultant}}
F3=(181.09i^181.09j^)\vec{F}_{3} = - (181.09\hat{i} - 181.09\hat{j})
F3=181.09i^+181.09j^\vec{F}_{3} = -181.09\hat{i} + 181.09\hat{j}
The third force needed is:
181.09i^+181.09j^N\boxed{-181.09\hat{i} + 181.09\hat{j} \, \mathrm{N}}

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