QuestionWrite a balanced nuclear equation for the following: The nuclide bismuth-214 undergoes alpha emission. Not submitted

Studdy Solution
Balance the nuclear equation. To find the daughter nuclide, subtract the mass number and atomic number of the alpha particle from the parent nuclide:
- Mass number: $214 - 4 = 210$ - Atomic number: $83 - 2 = 81$
The daughter nuclide is thallium-210 ($^{210}_{81}\text{Tl}$).
$$^{214}_{83}\text{Bi} \rightarrow ^{4}_{2}\text{He} + ^{210}_{81}\text{Tl}$$
The balanced nuclear equation for the alpha emission of bismuth-214 is:
$$^{214}_{83}\text{Bi} \rightarrow ^{4}_{2}\text{He} + ^{210}_{81}\text{Tl}$$