Math  /  Trigonometry

Question Write the equation of a cosine function with range [2,10][2,10], period 2π3\frac{2\pi}{3}, and midline 2-2.

Studdy Solution
Simplify the equation.
y=4cos(3x)2y = 4\cos(3x) - 2
The equation of the cosine function with a range of [2,10][2,10], period of 2π3\frac{2 \pi}{3} and a midline of -2 is y=4cos(3x)2y = 4\cos(3x) - 2.

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