QuestionWrite the following expression as a sum and/or difference of logarithms. Express powers as factors. $$\ln [e(x+9)]$$ $\ln [e(x+9)]=$ $\square$ (Simplify your answer.)

Studdy Solution
Simplify the expression using the known value $\ln e = 1$:
$$\ln e + \ln(x+9) = 1 + \ln(x+9)$$
The simplified expression is:
$$\boxed{1 + \ln(x+9)}$$