Question$x^{2}+(y+6)^{2}=36$

Studdy Solution
Determine the radius of the circle:
The radius $r$ is the square root of the right-hand side of the equation. Here, $r^{2} = 36$, so $r = \sqrt{36} = 6$.
The circle has a center at $(0, -6)$ and a radius of $6$.