QuestionSolve the differential equation: $y' - \frac{2x-1}{x^2-x} y = 1$.

Studdy Solution
Substitute the results from steps8 and10 into the solution formula to get the general solution of the differential equation.
$$y = e^{-\int p(x) dx} (\int e^{\int p(x) dx} q(x) dx + C) = \frac{x}{x-} (x + \ln|x-| + C)$$This is the general solution to the given differential equation.