Math  /  Algebra

Questiony=(x3)(x3)y=-(x-3)(x-3) x-intercepts: ( \square , 0) \square ,0)
Axis of Symmetry: \square
Vertex: \square y-intercept: (0, \square

Studdy Solution
To find the y-intercept, set x=0 x = 0 and solve for y y :
y=(03)2 y = -(0-3)^2 y=(3)2 y = -(3)^2 y=9 y = -9
Thus, the y-intercept is at (0,9) (0, -9) .
The x-intercepts are (3,0) (3, 0) , the axis of symmetry is x=3 x = 3 , the vertex is (3,0) (3, 0) , and the y-intercept is (0,9) (0, -9) .

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