Math / CalculusQuestiony′=y' = y′=y=lnx2+2xy = \ln{\frac{x^2 + 2}{x}}y=lnxx2+2Find the derivative of the function.Studdy SolutionThe derivative of y=lnx2+2xy = \ln{\frac{x^2 + 2}{x}}y=lnxx2+2 is y′=x2−2x(x2+2)y' = \frac{x^2 - 2}{x(x^2 + 2)}y′=x(x2+2)x2−2.View Full Solution - FreeWas this helpful?