Math  /  Data & Statistics

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You are conducting a multinomial hypothesis test (α=0.05(\alpha=0.05 ) for the claim that all 5 categories are equally likely to be selected. Complete the table. \begin{tabular}{|c|c|c|c|c|c|c|} \hline Category & Observed Frequency & \multicolumn{2}{|r|}{\begin{tabular}{l} Expected \\ Frequency \end{tabular}} & \multicolumn{3}{|l|}{(OE)2E\frac{(O-E)^{2}}{E}} \\ \hline A & 6 & 12.6 & & 3.457 & \checkmark & 0 \\ \hline B & 17 & 12.6 & & 1.537 & \checkmark & 080^{8} \\ \hline C & 6 & 12.6 & & 3.457 & \checkmark & 06 \\ \hline D & 16 & 12.6 & & 0.917 & \checkmark & 06 \\ \hline E & 18 & 12.6 & 0\checkmark 0 & 2.314 & \checkmark & 06 \\ \hline \end{tabular}
Report all answers accurate to three decimal places. But retain unrounded numbers for future calculations.
What is the chi-square test-statistic for this data? (Report answer accurate to three decimal places, and remember to use the unrounded Pearson residuals in your calculations.) χ2=11.6820\chi^{2}=11.682 \quad \checkmark 0^{\infty}
What are the degrees of freedom for this test? d.f. == \square 4 0
What is the pp-value for this sample? (Report answer accurate to four decimal places.) p -value = \square It may be best to use the =CHIDIST( ) function in a Spreadsheet to do this calculation. The pp-value is...

Studdy Solution
The chi-square test statistic is χ2=11.682\chi^{2} = 11.682.
The degrees of freedom are 44.
The p-value is 0.01970.0197.

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