Question$\lim _{x \rightarrow 1^{+}}-\ln x-1$

Studdy Solution
Evaluate the limit of $-\ln x - 1$ as $x \rightarrow 1^{+}$:
Since $\ln x \rightarrow 0$ as $x \rightarrow 1^{+}$, it follows that:
$-\ln x \rightarrow -0 = 0$
Thus, the expression $-\ln x - 1$ becomes:
$-\ln x - 1 \rightarrow 0 - 1 = -1$
Therefore, the limit is:
$\lim _{x \rightarrow 1^{+}}-\ln x-1 = -1$
The value of the limit is:
$\boxed{-1}$