Question010 (part 1 of 2 ) 10.0 points A crate is lifted vertically 1.5 m and then held at rest. The crate has weight 100 N (i.e., it is supported by an upward force of 100 N ).
How much work was done in lifting the crate from the ground to its final position?
1. 150 J
2. None of these
3. A bit less than 150 J
4. No work was done.
5. More than 150 J

Studdy Solution

STEP 1

1. The crate is lifted vertically.
2. The weight of the crate is $100 \, \text{N}$ .
3. The crate is lifted to a height of $1.5 \, \text{m}$ .
4. The force applied is constant and equal to the weight of the crate.

STEP 2

1. Recall the formula for work done.
2. Substitute the given values.
3. Calculate the work done.

STEP 3

Recall the formula for work done when a force is applied over a distance:
$W = F \times d$
where $W$ is the work done, $F$ is the force applied, and $d$ is the distance over which the force is applied.

STEP 4

Substitute the given values into the formula:
$W = F \times d$ $= 100 \, \text{N} \times 1.5 \, \text{m}$

STEP 5

Calculate the product:
$W = 100 \, \text{N} \times 1.5 \, \text{m}$ $= 150 \, \text{J}$
The work done in lifting the crate is:
$\boxed{150 \, \text{J}}$
Therefore, the correct answer is:
1. 150 J

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