Math  /  Calculus

Question1. [-/1 Points] DETAILS MY NOTES SCALCET9 4.9.006.
Find the most general antiderivative of the function. (Check your answer by differentiation. Use CC for the constant of the antiderivative. f(x)=x27x+8F(x)=\begin{array}{l} f(x)=x^{2}-7 x+8 \\ F(x)=\square \end{array} Need Help? Road It Submit Answer

Studdy Solution

STEP 1

1. We are given the function f(x)=x27x+8 f(x) = x^2 - 7x + 8 .
2. We need to find the most general antiderivative F(x) F(x) .
3. We will use C C as the constant of integration.

STEP 2

1. Identify the antiderivative of each term in the function separately.
2. Combine the antiderivatives to form the most general antiderivative.
3. Add the constant of integration C C .
4. Differentiate the antiderivative to check the solution.

STEP 3

Identify the antiderivative of each term:
- The antiderivative of x2 x^2 is x33 \frac{x^3}{3} . - The antiderivative of 7x -7x is 7x22 -\frac{7x^2}{2} . - The antiderivative of 8 8 is 8x 8x .

STEP 4

Combine the antiderivatives:
F(x)=x337x22+8x+C F(x) = \frac{x^3}{3} - \frac{7x^2}{2} + 8x + C

STEP 5

Add the constant of integration C C :
The most general antiderivative is:
F(x)=x337x22+8x+C F(x) = \frac{x^3}{3} - \frac{7x^2}{2} + 8x + C

STEP 6

Differentiate F(x) F(x) to check the solution:
F(x)=ddx(x337x22+8x+C) F'(x) = \frac{d}{dx} \left( \frac{x^3}{3} - \frac{7x^2}{2} + 8x + C \right)
F(x)=x27x+8 F'(x) = x^2 - 7x + 8
Since F(x)=f(x) F'(x) = f(x) , the solution is verified.
The most general antiderivative is:
x337x22+8x+C \boxed{\frac{x^3}{3} - \frac{7x^2}{2} + 8x + C}

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