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Math

Math Snap

PROBLEM

1. a. Express cos(x)\cos (x) in terms of cot(x)\cot (x) and csc(x)\csc (x).
b. Express csc(x)\csc (x) in terms of cos(x)\cos (x) and tan(x)\tan (x).

STEP 1

1. We are working with trigonometric identities and relationships.
2. We will use basic trigonometric identities to express one function in terms of others.
3. We assume x x is an angle where all trigonometric functions are defined.

STEP 2

1. Express cos(x)\cos(x) in terms of cot(x)\cot(x) and csc(x)\csc(x).
2. Express csc(x)\csc(x) in terms of cos(x)\cos(x) and tan(x)\tan(x).

STEP 3

Start with the identity for cot(x)\cot(x) and csc(x)\csc(x):
cot(x)=cos(x)sin(x)\cot(x) = \frac{\cos(x)}{\sin(x)} csc(x)=1sin(x)\csc(x) = \frac{1}{\sin(x)}

STEP 4

Solve the expression for cos(x)\cos(x) in terms of cot(x)\cot(x) and csc(x)\csc(x):
Since cot(x)=cos(x)sin(x)\cot(x) = \frac{\cos(x)}{\sin(x)}, we can express sin(x)\sin(x) in terms of csc(x)\csc(x):
sin(x)=1csc(x)\sin(x) = \frac{1}{\csc(x)} Substitute sin(x)\sin(x) into the expression for cot(x)\cot(x):
cot(x)=cos(x)1csc(x)=cos(x)csc(x)\cot(x) = \frac{\cos(x)}{\frac{1}{\csc(x)}} = \cos(x) \cdot \csc(x) Thus, cos(x)=cot(x)1csc(x)=cot(x)csc(x)\cos(x) = \cot(x) \cdot \frac{1}{\csc(x)} = \frac{\cot(x)}{\csc(x)}.

STEP 5

Start with the identity for tan(x)\tan(x) and cos(x)\cos(x):
tan(x)=sin(x)cos(x)\tan(x) = \frac{\sin(x)}{\cos(x)}

SOLUTION

Express sin(x)\sin(x) in terms of cos(x)\cos(x) and tan(x)\tan(x):
Rearrange the expression for tan(x)\tan(x):
sin(x)=tan(x)cos(x)\sin(x) = \tan(x) \cdot \cos(x) Since csc(x)=1sin(x)\csc(x) = \frac{1}{\sin(x)}, substitute the expression for sin(x)\sin(x):
csc(x)=1tan(x)cos(x)\csc(x) = \frac{1}{\tan(x) \cdot \cos(x)} Thus, csc(x)=1tan(x)cos(x)\csc(x) = \frac{1}{\tan(x) \cdot \cos(x)}.
The expressions are:
a. cos(x)=cot(x)csc(x)\cos(x) = \frac{\cot(x)}{\csc(x)}
b. csc(x)=1tan(x)cos(x)\csc(x) = \frac{1}{\tan(x) \cdot \cos(x)}

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