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Math

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PROBLEM

1. Circle all of the following polynomials that are DEGREE 2: [1 mark]
2x+34x2+3x1(x+3)(x2)(x+4)28\begin{array}{llll} 2 x+3 & -4 x^{2}+3 x-1 & (x+3)(x-2) & (x+4)^{2}-8 \end{array}

STEP 1

1. A polynomial of degree 2 is a quadratic polynomial, which has the highest power of x x as 2.
2. We need to identify which of the given expressions are quadratic polynomials.

STEP 2

1. Analyze each polynomial to determine its degree.
2. Circle the polynomials that are of degree 2.

STEP 3

Analyze the polynomial 2x+3 2x + 3 :
- The highest power of x x is 1.
- Therefore, it is not a degree 2 polynomial.

STEP 4

Analyze the polynomial 4x2+3x1 -4x^2 + 3x - 1 :
- The highest power of x x is 2.
- Therefore, it is a degree 2 polynomial.

STEP 5

Analyze the polynomial (x+3)(x2) (x+3)(x-2) :
- Expand the expression:
(x+3)(x2)=x22x+3x6=x2+x6 (x+3)(x-2) = x^2 - 2x + 3x - 6 = x^2 + x - 6 - The highest power of x x is 2.
- Therefore, it is a degree 2 polynomial.

STEP 6

Analyze the polynomial (x+4)28 (x+4)^2 - 8 :
- Expand the expression:
(x+4)28=(x2+8x+16)8=x2+8x+8 (x+4)^2 - 8 = (x^2 + 8x + 16) - 8 = x^2 + 8x + 8 - The highest power of x x is 2.
- Therefore, it is a degree 2 polynomial.

SOLUTION

Circle the polynomials that are of degree 2:
- 4x2+3x1 -4x^2 + 3x - 1
- (x+3)(x2) (x+3)(x-2)
- (x+4)28 (x+4)^2 - 8
The polynomials that are degree 2 are:
4x2+3x1, (x+3)(x2), (x+4)28 \boxed{-4x^2 + 3x - 1, \ (x+3)(x-2), \ (x+4)^2 - 8}

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