Math

QuestionCalculate the following:
1. (g+h)(x)(g+h)(x)
2. (hf)(x)(h-f)(x)
3. (fh)(x)(f-h)(x)
4. (gf)(x)(g \circ f)(x)
5. Functions: f(x)=x1f(x)=x-1, g(x)=x21g(x)=x^{2}-1, h(x)=3x32x1h(x)=3x^{3}-2x-1

Studdy Solution

STEP 1

Assumptions1. The functions are defined as follows - f(x)=x1f(x)=x-1 - g(x)=x1g(x)=x^{}-1 - h(x)=3x3x1h(x)=3 x^{3}- x-1 . We are required to find the following - (g+h)(x)(g+h)(x) - (hf)(x)(h-f)(x) - (fh)(x)(f-h)(x) - (gf)(x)\left(g^{\circ} f\right)(x)

STEP 2

First, let's find (g+h)(x)(g+h)(x). This operation means that we add the functions g(x)g(x) and h(x)h(x).
(g+h)(x)=g(x)+h(x)(g+h)(x) = g(x) + h(x)

STEP 3

Substitute the given functions g(x)g(x) and h(x)h(x) into the equation.
(g+h)(x)=(x21)+(3x32x1)(g+h)(x) = (x^{2}-1) + (3 x^{3}-2 x-1)

STEP 4

Combine like terms.
(g+h)(x)=3x3+x22x2(g+h)(x) =3x^{3} + x^{2} -2x -2

STEP 5

Next, let's find (hf)(x)(h-f)(x). This operation means that we subtract the function f(x)f(x) from h(x)h(x).
(hf)(x)=h(x)f(x)(h-f)(x) = h(x) - f(x)

STEP 6

Substitute the given functions h(x)h(x) and f(x)f(x) into the equation.
(hf)(x)=(3x32x1)(x1)(h-f)(x) = (3 x^{3}-2 x-1) - (x-1)

STEP 7

implify the equation.
(hf)(x)=3x32x1x+1(h-f)(x) =3x^{3} -2x -1 - x +1

STEP 8

Combine like terms.
(hf)(x)=3x33x(h-f)(x) =3x^{3} -3x

STEP 9

Next, let's find (fh)(x)(f-h)(x). This operation means that we subtract the function h(x)h(x) from f(x)f(x).
(fh)(x)=f(x)h(x)(f-h)(x) = f(x) - h(x)

STEP 10

Substitute the given functions f(x)f(x) and h(x)h(x) into the equation.
(fh)(x)=(x)(3x32x)(f-h)(x) = (x-) - (3 x^{3}-2 x-)

STEP 11

implify the equation.
(fh)(x)=x3x3+x(f-h)(x) = x - -3x^{3} +x -

STEP 12

Combine like terms.
(fh)(x)=x+x2(f-h)(x) = -x^{} +x -2

STEP 13

Finally, let's find (gf)(x)\left(g^{\circ} f\right)(x). This operation means that we substitute the function f(x)f(x) into g(x)g(x).
(gf)(x)=g(f(x))\left(g^{\circ} f\right)(x) = g(f(x))

STEP 14

Substitute the given function f(x)f(x) into g(x)g(x).
(gf)(x)=(f(x))2\left(g^{\circ} f\right)(x) = (f(x))^{2}-

STEP 15

Substitute the given function f(x)f(x) into the equation.
(gf)(x)=(x)2\left(g^{\circ} f\right)(x) = (x-)^{2}-

STEP 16

Expand the square.
(gf)(x)=x22x+\left(g^{\circ} f\right)(x) = x^{2} -2x + -

STEP 17

Combine like terms.
(gf)(x)=x22x\left(g^{\circ} f\right)(x) = x^{2} -2xSo, the solutions are. (g+h)(x)=3x3+x22x2(g+h)(x) =3x^{3} + x^{2} -2x -2
2. (hf)(x)=3x33x(h-f)(x) =3x^{3} -3x
3. (fh)(x)=3x3+3x2(f-h)(x) = -3x^{3} +3x -2
4. (gf)(x)=x22x\left(g^{\circ} f\right)(x) = x^{2} -2x

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