Math

Question10. A car experiences a centripetal acceleration of 4.4 m/s24.4 \mathrm{~m} / \mathrm{s}^{2} as it rounds a corner with a speed of 15 m/s15 \mathrm{~m} / \mathrm{s}. What is the radius of the corner? (51.12m)

Studdy Solution

STEP 1

1. The car is moving in a circular path.
2. The centripetal acceleration is 4.4m/s2 4.4 \, \mathrm{m/s}^2 .
3. The speed of the car is 15m/s 15 \, \mathrm{m/s} .

STEP 2

1. Recall the formula for centripetal acceleration.
2. Rearrange the formula to solve for the radius.
3. Substitute the given values.
4. Calculate the radius.

STEP 3

Recall the formula for centripetal acceleration:
ac=v2r a_c = \frac{v^2}{r}
where ac a_c is the centripetal acceleration, v v is the speed, and r r is the radius of the circular path.

STEP 4

Rearrange the formula to solve for the radius r r :
r=v2ac r = \frac{v^2}{a_c}

STEP 5

Substitute the given values into the formula:
r=(15m/s)24.4m/s2 r = \frac{(15 \, \mathrm{m/s})^2}{4.4 \, \mathrm{m/s}^2}

STEP 6

Calculate the radius:
r=225m2/s24.4m/s2 r = \frac{225 \, \mathrm{m}^2/\mathrm{s}^2}{4.4 \, \mathrm{m/s}^2} r51.14m r \approx 51.14 \, \mathrm{m}
The radius of the corner is approximately:
51.14m \boxed{51.14 \, \mathrm{m}}

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