Solve a problem of your own!
Download the Studdy App!

Math

Math Snap

PROBLEM

10. Factor the following completely: 15x227x615 x^{2}-27 x-6

STEP 1

What is this asking?
We need to break down this expression 15x227x615x^2 - 27x - 6 into smaller pieces multiplied together, kind of like finding the prime factors of a number, but with xs!
Watch out!
Don't forget to look for common factors first!
It makes everything easier.
Also, double-check your answer by multiplying the factors back together.
It should match the original expression.

STEP 2

1. Find the Greatest Common Factor (GCF)
2. Factor the Trinomial

STEP 3

Let's look at our expression: 15x227x615x^2 - 27x - 6.
We want to find the biggest number that divides evenly into all three coefficients (15, -27, and -6).
Think about what numbers go into all of them.

STEP 4

Looks like 3 is the greatest common factor!
So, we can factor out a 3 from each term: 15x227x6=3(5x29x2)15x^2 - 27x - 6 = 3(5x^2 - 9x - 2).
See how we divided each term by 3?
Now, we're left with a simpler trinomial inside the parentheses.

STEP 5

Now, we need to factor 5x29x25x^2 - 9x - 2.
We're looking for two binomials that multiply together to give us this trinomial.
Since the x squared term has a coefficient of 5, we know one binomial will start with 5x5x and the other with xx.
So, we have (5x   )(x   )(5x \ \ \ )(x \ \ \ ).

STEP 6

Next, let's look at the constant term, which is -2.
We need two numbers that multiply to -2.
Our options are 1 and -2, or -1 and 2.

STEP 7

Now comes the tricky part!
We need to place these numbers in our binomials so that when we multiply everything out, the x term becomes -9xx.
Let's try 1 and -2. (5x+1)(x2)(5x + 1)(x - 2) gives us 5x210x+x2=5x29x25x^2 - 10x + x - 2 = 5x^2 - 9x - 2.
BOOM! We found it!

SOLUTION

So, the completely factored form of 15x227x615x^2 - 27x - 6 is 3(5x+1)(x2)3(5x + 1)(x - 2).
Remember, we factored out the 3 at the beginning!
Don't leave it out of the final answer.

Was this helpful?
banner

Start understanding anything

Get started now for free.

OverviewParentsContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord