Math  /  Algebra

Question11. \qquad (a+3b)(a+3b)=(a+3 b)(a+3 b)=
12. \qquad (3xy+6)(3xy6)=(3 x y+6)(3 x y-6)=
13. \qquad (m2)(m2)=(m-2)(m-2)=
14. \qquad (3t2)(3t2)=(3 t-2)(3 t-2)=
15. \qquad (x5)(x+5)=(x-5)(x+5)=
16. \qquad (8r2s24)(8r2s24)=\left(8 r^{2} s^{2}-4\right)\left(8 r^{2} s^{2}-4\right)=
17. \qquad (a+b)2=(a+b)^{2}=
18. \qquad (a+b)(ab)=(a+b)(a-b)=
19. \qquad (2abc)2=(2 a b-c)^{2}=
20. \qquad (2ab+c)(2abc)=(2 a b+c)(2 a b-c)=

Studdy Solution

STEP 1

1. We are given multiple algebraic expressions to simplify or expand.
2. We will use algebraic identities such as the square of a binomial and the difference of squares.
3. Each expression will be treated independently.

STEP 2

1. Simplify or expand each expression using appropriate algebraic identities.
2. Calculate or express the result for each expression.

STEP 3

Expression 11: (a+3b)(a+3b)(a+3b)(a+3b)
This is a square of a binomial, which can be expanded using the identity (x+y)2=x2+2xy+y2(x+y)^2 = x^2 + 2xy + y^2.
(a+3b)2=a2+2(a)(3b)+(3b)2 (a+3b)^2 = a^2 + 2(a)(3b) + (3b)^2
=a2+6ab+9b2 = a^2 + 6ab + 9b^2

STEP 4

Expression 12: (3xy+6)(3xy6)(3xy+6)(3xy-6)
This is a difference of squares, which can be simplified using the identity (x+y)(xy)=x2y2(x+y)(x-y) = x^2 - y^2.
(3xy+6)(3xy6)=(3xy)262 (3xy+6)(3xy-6) = (3xy)^2 - 6^2
=9x2y236 = 9x^2y^2 - 36

STEP 5

Expression 13: (m2)(m2)(m-2)(m-2)
This is a square of a binomial, which can be expanded using the identity (xy)2=x22xy+y2(x-y)^2 = x^2 - 2xy + y^2.
(m2)2=m22(m)(2)+22 (m-2)^2 = m^2 - 2(m)(2) + 2^2
=m24m+4 = m^2 - 4m + 4

STEP 6

Expression 14: (3t2)(3t2)(3t-2)(3t-2)
This is a square of a binomial, which can be expanded using the identity (xy)2=x22xy+y2(x-y)^2 = x^2 - 2xy + y^2.
(3t2)2=(3t)22(3t)(2)+22 (3t-2)^2 = (3t)^2 - 2(3t)(2) + 2^2
=9t212t+4 = 9t^2 - 12t + 4

STEP 7

Expression 15: (x5)(x+5)(x-5)(x+5)
This is a difference of squares, which can be simplified using the identity (xy)(x+y)=x2y2(x-y)(x+y) = x^2 - y^2.
(x5)(x+5)=x252 (x-5)(x+5) = x^2 - 5^2
=x225 = x^2 - 25

STEP 8

Expression 16: (8r2s24)(8r2s24)(8r^2s^2-4)(8r^2s^2-4)
This is a square of a binomial, which can be expanded using the identity (xy)2=x22xy+y2(x-y)^2 = x^2 - 2xy + y^2.
(8r2s24)2=(8r2s2)22(8r2s2)(4)+42 (8r^2s^2-4)^2 = (8r^2s^2)^2 - 2(8r^2s^2)(4) + 4^2
=64r4s464r2s2+16 = 64r^4s^4 - 64r^2s^2 + 16

STEP 9

Expression 17: (a+b)2(a+b)^2
This is a square of a binomial, which can be expanded using the identity (x+y)2=x2+2xy+y2(x+y)^2 = x^2 + 2xy + y^2.
(a+b)2=a2+2ab+b2 (a+b)^2 = a^2 + 2ab + b^2

STEP 10

Expression 18: (a+b)(ab)(a+b)(a-b)
This is a difference of squares, which can be simplified using the identity (x+y)(xy)=x2y2(x+y)(x-y) = x^2 - y^2.
(a+b)(ab)=a2b2 (a+b)(a-b) = a^2 - b^2

STEP 11

Expression 19: (2abc)2(2ab-c)^2
This is a square of a binomial, which can be expanded using the identity (xy)2=x22xy+y2(x-y)^2 = x^2 - 2xy + y^2.
(2abc)2=(2ab)22(2ab)(c)+c2 (2ab-c)^2 = (2ab)^2 - 2(2ab)(c) + c^2
=4a2b24abc+c2 = 4a^2b^2 - 4abc + c^2

STEP 12

Expression 20: (2ab+c)(2abc)(2ab+c)(2ab-c)
This is a difference of squares, which can be simplified using the identity (x+y)(xy)=x2y2(x+y)(x-y) = x^2 - y^2.
(2ab+c)(2abc)=(2ab)2c2 (2ab+c)(2ab-c) = (2ab)^2 - c^2
=4a2b2c2 = 4a^2b^2 - c^2

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