QuestionSolve for $y$ in the equation $11-\frac{1}{2} y=3+6 x$ .

Studdy Solution

STEP 1

Assumptions1. The given equation is $11-\frac{1}{} y=3+6 x$ . We need to isolate $y$ to find its value in terms of $x$

STEP 2

First, let's get all the terms with $y$ on one side of the equation and the rest on the other side. We can do this by subtracting $$ from both sides of the equation.
$11 - -\frac{1}{2} y = +6x -$

STEP 3

implify the equation.
$8 -\frac{1}{2} y =6x$

STEP 4

Now, let's get $y$ alone on one side of the equation. We can do this by multiplying every term by $-2$ to get rid of the fraction.
$-2 \times8 + y = -2 \times6x$

STEP 5

implify the equation.
$-16 + y = -12x$

STEP 6

Now, let's get $y$ alone on one side of the equation. We can do this by adding $16$ to both sides of the equation.
$y = -12x +16$ So, the solution to the equation $11-\frac{1}{2} y=3+6 x$ is $y = -12x +16$ .

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QuestionSolve for $y$ in the equation $11-\frac{1}{2} y=3+6 x$ .

Studdy Solution

STEP 1

Assumptions1. The given equation is $11-\frac{1}{} y=3+6 x$ . We need to isolate $y$ to find its value in terms of $x$

STEP 2

First, let's get all the terms with $y$ on one side of the equation and the rest on the other side. We can do this by subtracting $$ from both sides of the equation.
$11 - -\frac{1}{2} y = +6x -$

STEP 3

implify the equation.
$8 -\frac{1}{2} y =6x$

STEP 4

Now, let's get $y$ alone on one side of the equation. We can do this by multiplying every term by $-2$ to get rid of the fraction.
$-2 \times8 + y = -2 \times6x$

STEP 5

implify the equation.
$-16 + y = -12x$

STEP 6

Now, let's get $y$ alone on one side of the equation. We can do this by adding $16$ to both sides of the equation.
$y = -12x +16$ So, the solution to the equation $11-\frac{1}{2} y=3+6 x$ is $y = -12x +16$ .

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QuestionSolve for yyy in the equation 11−12y=3+6x11-\frac{1}{2} y=3+6 x11−21​y=3+6x.

Studdy Solution

STEP 1

Assumptions1. The given equation is 11−1y=3+6x11-\frac{1}{} y=3+6 x11−1​y=3+6x . We need to isolate yyy to find its value in terms of xxx

STEP 2

First, let's get all the terms with yyy on one side of the equation and the rest on the other side. We can do this by subtracting $$ from both sides of the equation.11−−12y=+6x−11 - -\frac{1}{2} y = +6x -11−−21​y=+6x−

STEP 3

implify the equation.8−12y=6x8 -\frac{1}{2} y =6x8−21​y=6x

STEP 4

Now, let's get yyy alone on one side of the equation. We can do this by multiplying every term by −2-2−2 to get rid of the fraction.−2×8+y=−2×6x-2 \times8 + y = -2 \times6x−2×8+y=−2×6x

STEP 5

implify the equation.−16+y=−12x-16 + y = -12x−16+y=−12x

STEP 6

Now, let's get yyy alone on one side of the equation. We can do this by adding 161616 to both sides of the equation.y=−12x+16y = -12x +16y=−12x+16So, the solution to the equation 11−12y=3+6x11-\frac{1}{2} y=3+6 x11−21​y=3+6x is y=−12x+16y = -12x +16y=−12x+16.

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Studdy solves anything!

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QuestionSolve for $y$ in the equation $11-\frac{1}{2} y=3+6 x$ .

Assumptions1. The given equation is $11-\frac{1}{} y=3+6 x$ . We need to isolate $y$ to find its value in terms of $x$

First, let's get all the terms with $y$ on one side of the equation and the rest on the other side. We can do this by subtracting $$ from both sides of the equation.
$11 - -\frac{1}{2} y = +6x -$

implify the equation.
$8 -\frac{1}{2} y =6x$

Now, let's get $y$ alone on one side of the equation. We can do this by multiplying every term by $-2$ to get rid of the fraction.
$-2 \times8 + y = -2 \times6x$

implify the equation.
$-16 + y = -12x$

Now, let's get $y$ alone on one side of the equation. We can do this by adding $16$ to both sides of the equation.
$y = -12x +16$ So, the solution to the equation $11-\frac{1}{2} y=3+6 x$ is $y = -12x +16$ .