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Math

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PROBLEM

(12) 15x+3=14x+3\frac{1}{5} x+3=-\frac{1}{4} x+3

STEP 1

1. The equation 15x+3=14x+3\frac{1}{5}x + 3 = -\frac{1}{4}x + 3 is a linear equation in one variable.
2. The goal is to solve for x x .
3. The equation involves fractions, which require careful manipulation.

STEP 2

1. Simplify the equation by eliminating the constant terms on both sides.
2. Combine like terms to isolate the variable x x .
3. Solve for x x .

STEP 3

First, observe that both sides of the equation have a constant term +3 +3 . We can subtract 3 3 from both sides to simplify the equation:
15x+33=14x+33 \frac{1}{5}x + 3 - 3 = -\frac{1}{4}x + 3 - 3 This simplifies to:
15x=14x \frac{1}{5}x = -\frac{1}{4}x

STEP 4

Next, we need to combine the x x -terms. To do this, add 14x\frac{1}{4}x to both sides to get all x x -terms on one side:
15x+14x=0 \frac{1}{5}x + \frac{1}{4}x = 0

STEP 5

To combine the fractions, find a common denominator. The common denominator of 5 and 4 is 20. Convert each fraction:
420x+520x=0 \frac{4}{20}x + \frac{5}{20}x = 0 Combine the fractions:
920x=0 \frac{9}{20}x = 0

SOLUTION

To solve for x x , multiply both sides by the reciprocal of 920\frac{9}{20}, which is 209\frac{20}{9}:
x=0×209 x = 0 \times \frac{20}{9} Simplify:
x=0 x = 0 The solution is:
0 \boxed{0}

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