QuestionSolve for $x$ in the equation: $12-\frac{4}{5}(x+15)=4$ .

Studdy Solution

STEP 1

Assumptions1. The equation given is $12-\frac{4}{5}(x+15)=4$ . We are solving for the variable $x$

STEP 2

First, we need to distribute the $\frac{4}{5}$ to both $x$ and $15$ inside the parentheses.
$12 - \frac{4}{5}x - \frac{4}{5} \cdot15 =4$

STEP 3

Now, calculate the multiplication of $\frac{}{5}$ and $15$ .
$12 - \frac{}{5}x -12 =$

STEP 4

implify the left side of the equation by subtracting $12$ from $12$ .
$- \frac{4}{}x =4$

STEP 5

To isolate $x$ , we need to divide both sides of the equation by $-\frac{4}{5}$ . $x = \frac{4}{- \frac{4}{5}}$

STEP 6

Now, calculate the division of $4$ by $-\frac{4}{5}$ .
$x = -5$ So, the solution to the equation $12-\frac{4}{5}(x+15)=4$ is $x = -5$ .

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QuestionSolve for $x$ in the equation: $12-\frac{4}{5}(x+15)=4$ .

Studdy Solution

STEP 1

Assumptions1. The equation given is $12-\frac{4}{5}(x+15)=4$ . We are solving for the variable $x$

STEP 2

First, we need to distribute the $\frac{4}{5}$ to both $x$ and $15$ inside the parentheses.
$12 - \frac{4}{5}x - \frac{4}{5} \cdot15 =4$

STEP 3

Now, calculate the multiplication of $\frac{}{5}$ and $15$ .
$12 - \frac{}{5}x -12 =$

STEP 4

implify the left side of the equation by subtracting $12$ from $12$ .
$- \frac{4}{}x =4$

STEP 5

To isolate $x$ , we need to divide both sides of the equation by $-\frac{4}{5}$ . $x = \frac{4}{- \frac{4}{5}}$

STEP 6

Now, calculate the division of $4$ by $-\frac{4}{5}$ .
$x = -5$ So, the solution to the equation $12-\frac{4}{5}(x+15)=4$ is $x = -5$ .

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QuestionSolve for xxx in the equation: 12−45(x+15)=412-\frac{4}{5}(x+15)=412−54​(x+15)=4.

Studdy Solution

STEP 1

Assumptions1. The equation given is 12−45(x+15)=412-\frac{4}{5}(x+15)=412−54​(x+15)=4 . We are solving for the variable xxx

STEP 2

First, we need to distribute the 45\frac{4}{5}54​ to both xxx and 151515 inside the parentheses.12−45x−45⋅15=412 - \frac{4}{5}x - \frac{4}{5} \cdot15 =412−54​x−54​⋅15=4

STEP 3

Now, calculate the multiplication of 5\frac{}{5}5​ and 151515.12−5x−12=12 - \frac{}{5}x -12 =12−5​x−12=

STEP 4

implify the left side of the equation by subtracting 121212 from 121212.−4x=4- \frac{4}{}x =4−4​x=4

STEP 5

To isolate xxx, we need to divide both sides of the equation by −45-\frac{4}{5}−54​.x=4−45x = \frac{4}{- \frac{4}{5}}x=−54​4​

STEP 6

Now, calculate the division of 444 by −45-\frac{4}{5}−54​.x=−5x = -5x=−5So, the solution to the equation 12−45(x+15)=412-\frac{4}{5}(x+15)=412−54​(x+15)=4 is x=−5x = -5x=−5.

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QuestionSolve for $x$ in the equation: $12-\frac{4}{5}(x+15)=4$ .

Assumptions1. The equation given is $12-\frac{4}{5}(x+15)=4$ . We are solving for the variable $x$

First, we need to distribute the $\frac{4}{5}$ to both $x$ and $15$ inside the parentheses.
$12 - \frac{4}{5}x - \frac{4}{5} \cdot15 =4$

Now, calculate the multiplication of $\frac{}{5}$ and $15$ .
$12 - \frac{}{5}x -12 =$

implify the left side of the equation by subtracting $12$ from $12$ .
$- \frac{4}{}x =4$

To isolate $x$ , we need to divide both sides of the equation by $-\frac{4}{5}$ . $x = \frac{4}{- \frac{4}{5}}$

Now, calculate the division of $4$ by $-\frac{4}{5}$ .
$x = -5$ So, the solution to the equation $12-\frac{4}{5}(x+15)=4$ is $x = -5$ .