Math

QuestionCalculate 12×(3+22)÷21012 \times (3 + 2^{2}) \div 2 - 10.

Studdy Solution

STEP 1

Assumptions1. We are following the order of operations, also known as BIDMAS or PEMAS, which stands for Brackets, Indices (or Exponents), Division and Multiplication (from left to right), Addition and Subtraction (from left to right).

STEP 2

First, we need to solve the operation within the brackets.
12×(+22)÷21012 \times\left(+2^{2}\right) \div2-10

STEP 3

olve the exponent (or index) within the brackets.
22=2^{2} =So, the expression becomes12×(3+)÷21012 \times\left(3+\right) \div2-10

STEP 4

Now, add the numbers within the brackets.
3+4=73+4 =7So, the expression becomes12×7÷21012 \times7 \div2-10

STEP 5

Next, perform the multiplication operation.
12×7=8412 \times7 =84So, the expression becomes84÷21084 \div2-10

STEP 6

Now, perform the division operation.
84÷2=4284 \div2 =42So, the expression becomes421042-10

STEP 7

Finally, perform the subtraction operation.
4210=3242-10 =32So, the solution to the problem is32.

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