Math  /  Numbers & Operations

Question12. Which of the following uses properties of operations to help find 27×1427 \times 14 ? 4.Nso.2.2. (A) 20+7+10+420+7+10+4 (B) 20×7×10×420 \times 7 \times 10 \times 4 (C) 27+1427+14 (D) (20+7)×(10+4)(20+7) \times(10+4)

Studdy Solution

STEP 1

What is this asking? Which expression uses the distributive property to calculate 271427 \cdot 14? Watch out! Don't just multiply 2727 and 1414 directly.
We're looking for a clever way to break it down!

STEP 2

1. Break down the numbers
2. Apply the distributive property
3. Check the answers

STEP 3

Let's **break down** our numbers into tens and ones.
We can write 2727 as 20+720 + 7, right?
And 1414 can be written as 10+410 + 4.
This makes things easier to work with!

STEP 4

Now, let's use the **distributive property**.
Think of it like this: we're multiplying each part of the first number (2020 and 77) by each part of the second number (1010 and 44).
So, we get (20+7)(10+4)(20 + 7) \cdot (10 + 4).
This is how we **expand** the multiplication!

STEP 5

If we were to calculate this, we'd multiply 2020 by 1010 and 2020 by 44, then 77 by 1010 and 77 by 44.
That gives us 2010+204+710+7420 \cdot 10 + 20 \cdot 4 + 7 \cdot 10 + 7 \cdot 4.
This simplifies to 200+80+70+28200 + 80 + 70 + 28, which then adds up to 378378.

STEP 6

Let's see which answer choice matches our **distributive property** setup.
Option (A) is just adding all the parts separately, so that's not it.
Option (B) is multiplying the parts separately, also not what we want.
Option (C) is simply adding 2727 and 1414, definitely not right.
Option (D) is (20+7)(10+4)(20 + 7) \cdot (10 + 4), which is **exactly** what we got!

STEP 7

The answer is (D)! (20+7)(10+4)(20 + 7) \cdot (10 + 4) correctly uses the distributive property to find 271427 \cdot 14.

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