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PROBLEM

14. 17. Find the temperature coefficient of resistance of iron at 20C20^{\circ} \mathrm{C}, if iron has an inferred zero resistance temperature 162C-162^{\circ} \mathrm{C} ? Ans 0,00551/C0,00551 /{ }^{\circ} \mathrm{C}-

STEP 1

1. The temperature coefficient of resistance (α\alpha) is a measure of how much the resistance of a material changes with temperature.
2. The formula for the temperature coefficient of resistance is given by:
$$ \alpha = \frac{1}{R_0} \cdot \frac{R - R_0}{T - T_0}
\] where R0R_0 is the resistance at the reference temperature T0T_0, and RR is the resistance at temperature TT.
3. The inferred zero resistance temperature is the temperature at which the resistance is theoretically zero.

STEP 2

1. Identify the known values and the formula to use.
2. Substitute the known values into the formula.
3. Solve for the temperature coefficient of resistance (α\alpha).

STEP 3

Identify the known values and the formula to use.
- The reference temperature T0=20CT_0 = 20^{\circ} \mathrm{C}.
- The inferred zero resistance temperature T=162CT = -162^{\circ} \mathrm{C}.
- The formula to use is:
$$ \alpha = \frac{1}{T_0 - T}
\]

STEP 4

Substitute the known values into the formula.
Substitute T0=20CT_0 = 20^{\circ} \mathrm{C} and T=162CT = -162^{\circ} \mathrm{C} into the formula:
α=120(162)\alpha = \frac{1}{20 - (-162)}

SOLUTION

Solve for the temperature coefficient of resistance (α\alpha).
Simplify the expression:
α=120+162\alpha = \frac{1}{20 + 162} α=1182\alpha = \frac{1}{182} Calculate the value:
α0.00549/C\alpha \approx 0.00549 /{ }^{\circ} \mathrm{C} The temperature coefficient of resistance of iron at 20C20^{\circ} \mathrm{C} is approximately 0.00549/C0.00549 /{ }^{\circ} \mathrm{C}.
Note: The provided answer 0.00551/C0.00551 /{ }^{\circ} \mathrm{C} might be due to rounding differences.

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