Math  /  Algebra

Question17 Write an equation of the line below in slope intercept form: y=mx+by=m x+b

Studdy Solution

STEP 1

What is this asking? We need to find the equation of a line in the form y=mx+by = mx + b, given a graph showing the line passing through (0,1)(0, 1) and (4,1)(4, -1). Watch out! Don't mix up the *x* and *y* coordinates!
Also, remember that the *b* in the equation is the *y*-intercept, not the *x*-intercept!

STEP 2

1. Find the slope.
2. Find the y-intercept.
3. Write the equation.

STEP 3

Alright, let's **start** by finding the **slope**, which tells us how steep our line is!
The slope, usually represented by *m*, is the change in *y* divided by the change in *x*.
We can use our two given points to find this.

STEP 4

Our points are (0,1)(0, 1) and (4,1)(4, -1).
Let's label them!
Let's call (0,1)(0, 1) point 1, so x1=0x_1 = 0 and y1=1y_1 = 1.
And (4,1)(4, -1) is point 2, so x2=4x_2 = 4 and y2=1y_2 = -1.

STEP 5

The formula for the slope is: m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1} Let's plug in those values! m=1140m = \frac{-1 - 1}{4 - 0} m=24m = \frac{-2}{4}m=12m = -\frac{1}{2}So, our **slope** is 12-\frac{1}{2}!
This means for every **1 unit** we move to the right along the *x*-axis, we move **down** 12\frac{1}{2} a unit along the *y*-axis.

STEP 6

The **y-intercept** is the point where the line crosses the *y*-axis.
This happens when x=0x = 0.
Look closely at the graph!
We're given the point (0,1)(0, 1), which means our line crosses the *y*-axis at y=1y = 1.
So, our **y-intercept**, which we call *b*, is **1**!

STEP 7

We've got our **slope**, m=12m = -\frac{1}{2}, and our **y-intercept**, b=1b = 1.
Now we just plug them into the **slope-intercept form**: y=mx+by = mx + b y=12x+1y = -\frac{1}{2}x + 1And there we have it!

STEP 8

The equation of the line is y=12x+1y = -\frac{1}{2}x + 1.

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