Math  /  Trigonometry

Question2) semplifica l'espressione cos(πα)sin(3π2+α)sin2αtan(απ)+tan(π2+α)\frac{\cos (\pi-\alpha) \sin \left(\frac{3 \pi}{2}+\alpha\right)}{\sin ^{2} \alpha} \tan (\alpha-\pi)+\tan \left(\frac{\pi}{2}+\alpha\right)

Studdy Solution

STEP 1

1. We are asked to simplify the given trigonometric expression.
2. We will use trigonometric identities to simplify the expression.

STEP 2

1. Simplify each trigonometric function using identities.
2. Simplify the entire expression by combining terms.

STEP 3

Simplify cos(πα)\cos(\pi - \alpha) using the identity cos(πα)=cos(α)\cos(\pi - \alpha) = -\cos(\alpha).
cos(πα)=cos(α) \cos(\pi - \alpha) = -\cos(\alpha)

STEP 4

Simplify sin(3π2+α)\sin\left(\frac{3\pi}{2} + \alpha\right) using the identity sin(3π2+α)=cos(α)\sin\left(\frac{3\pi}{2} + \alpha\right) = -\cos(\alpha).
sin(3π2+α)=cos(α) \sin\left(\frac{3\pi}{2} + \alpha\right) = -\cos(\alpha)

STEP 5

Simplify tan(απ)\tan(\alpha - \pi) using the identity tan(απ)=tan(α)\tan(\alpha - \pi) = \tan(\alpha).
tan(απ)=tan(α) \tan(\alpha - \pi) = \tan(\alpha)

STEP 6

Simplify tan(π2+α)\tan\left(\frac{\pi}{2} + \alpha\right) using the identity tan(π2+α)=cot(α)\tan\left(\frac{\pi}{2} + \alpha\right) = -\cot(\alpha).
tan(π2+α)=cot(α) \tan\left(\frac{\pi}{2} + \alpha\right) = -\cot(\alpha)

STEP 7

Substitute the simplified expressions back into the original expression:
cos(πα)sin(3π2+α)sin2αtan(απ)+tan(π2+α)\frac{\cos (\pi-\alpha) \sin \left(\frac{3 \pi}{2}+\alpha\right)}{\sin ^{2} \alpha} \tan (\alpha-\pi) + \tan \left(\frac{\pi}{2}+\alpha\right)
becomes:
(cos(α))(cos(α))sin2(α)tan(α)cot(α)\frac{(-\cos(\alpha))(-\cos(\alpha))}{\sin^2(\alpha)} \tan(\alpha) - \cot(\alpha)

STEP 8

Simplify the first term:
cos2(α)sin2(α)tan(α)=cot2(α)tan(α)\frac{\cos^2(\alpha)}{\sin^2(\alpha)} \tan(\alpha) = \cot^2(\alpha) \tan(\alpha)
Since cot(α)=1tan(α)\cot(\alpha) = \frac{1}{\tan(\alpha)}, we have:
cot2(α)tan(α)=1tan(α)tan(α)=cot(α)\cot^2(\alpha) \tan(\alpha) = \frac{1}{\tan(\alpha)} \tan(\alpha) = \cot(\alpha)

STEP 9

Combine the terms:
cot(α)cot(α)=0\cot(\alpha) - \cot(\alpha) = 0
The simplified expression is:
0 \boxed{0}

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