Studdy AI Logo
Math  /  Geometry

Question2. The equation of a circle is x2+y2=121x^{2}+y^{2}=121. Determine the radius. a. 10 units b. 12.1 units c. 11 units d. 22 units
3. Which point is on the circle with equation x2+v2=26?x^{2}+v^{2}=26 ?

Studdy Solution

STEP 1

1. The equation of a circle is given in the standard form x2+y2=r2 x^2 + y^2 = r^2 .
2. We need to determine the radius from the given equation.
3. We need to verify which point lies on the circle by substituting into the equation.

STEP 2

1. Determine the radius of the circle from the equation x2+y2=121 x^2 + y^2 = 121 .
2. Verify which point lies on the circle with equation x2+v2=26 x^2 + v^2 = 26 .

STEP 3

Identify the standard form of the circle equation:
The standard form is x2+y2=r2 x^2 + y^2 = r^2 .

STEP 4

Compare the given equation x2+y2=121 x^2 + y^2 = 121 with the standard form:
Here, r2=121 r^2 = 121 .

STEP 5

Solve for the radius r r :
r=121=11 r = \sqrt{121} = 11
The radius of the circle is 11 \boxed{11} units.

STEP 6

Verify which point lies on the circle with equation x2+v2=26 x^2 + v^2 = 26 .
Consider a point (a,b) (a, b) . Substitute into the equation:
a2+b2=26 a^2 + b^2 = 26

STEP 7

Test potential points:
For example, test point (3,5) (3, 5) :
32+52=9+25=34≠26 3^2 + 5^2 = 9 + 25 = 34 \neq 26
Test point (1,5) (1, 5) :
12+52=1+25=26 1^2 + 5^2 = 1 + 25 = 26
The point (1,5) (1, 5) is on the circle.

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord