Math

QuestionSimplify 2(a2b1)2\left(a^{2} b^{-1}\right) and express with positive exponents.

Studdy Solution

STEP 1

Assumptions1. We are given the expression (ab1)\left(a^{} b^{-1}\right). We need to simplify the expression using the properties of exponents3. In the final answer, only positive exponents should be included

STEP 2

First, we distribute the2 across the terms inside the parentheses.
2(a2b1)=2a22b12\left(a^{2} b^{-1}\right) =2a^{2} \cdot2b^{-1}

STEP 3

Next, we simplify the expression by multiplying the coefficients.
2a22b1=a2b12a^{2} \cdot2b^{-1} =a^{2}b^{-1}

STEP 4

Now, we need to convert the negative exponent to a positive exponent. We can do this by taking the reciprocal of the base.
4a2b1=4a21b14a^{2}b^{-1} =4a^{2} \cdot \frac{1}{b^{1}}

STEP 5

Finally, we rewrite the expression to only include positive exponents.
4a21b1=4a2b4a^{2} \cdot \frac{1}{b^{1}} = \frac{4a^{2}}{b}So, the simplified expression is 4a2b\frac{4a^{2}}{b}.

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord