Math

QuestionSolve the equation 2x3=x22x - 3 = |x - 2|.

Studdy Solution

STEP 1

Assumptions1. The equation given is x3=xx -3 = |x -| . The absolute value of a number is its distance from zero on the number line, which is always positive or zero.
3. The equation can be split into two cases, one for x0x - \geq0 and one for x<0x - <0.

STEP 2

First, we'll solve for the case where x20x -2 \geq0. This means the absolute value can be removed.
2x=x22x - = x -2

STEP 3

To isolate xx, subtract xx from both sides of the equation.
2xx=3+22x - x = -3 +2

STEP 4

implify the equation to find the value of xx.
x=1x = -1

STEP 5

Now, we need to check if the solution x=1x = -1 satisfies the condition x20x -2 \geq0. If it does not, then it is not a valid solution.
120-1 -2 \geq0This is not true, so x=1x = -1 is not a solution.

STEP 6

Next, we'll solve for the case where x2<0x -2 <0. This means the absolute value becomes the negative of the expression inside.
2x3=(x2)2x -3 = -(x -2)

STEP 7

implify the right side of the equation.
2x3=x+22x -3 = -x +2

STEP 8

To isolate xx, add xx to both sides of the equation.
2x+x=2+32x + x =2 +3

STEP 9

implify the equation to find the value of xx.
3x=53x =5x=53x = \frac{5}{3}

STEP 10

Now, we need to check if the solution x=53x = \frac{5}{3} satisfies the condition x2<0x -2 <0. If it does not, then it is not a valid solution.
532<0\frac{5}{3} -2 <0This is true, so x=53x = \frac{5}{3} is a solution.
The solution to the equation 2x3=x22x -3 = |x -2| is x=53x = \frac{5}{3}.

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