Math  /  Algebra

Question2x2 x \quad 28.) f(x)=1x+3f(x)=\frac{1}{x+3}

Studdy Solution

STEP 1

1. The function given is f(x)=1x+3 f(x) = \frac{1}{x+3} .
2. The function is a rational function, which means it is undefined where the denominator is zero.
3. We need to determine the domain of the function by identifying values of x x that make the denominator zero.

STEP 2

1. Identify the denominator of the function.
2. Determine the values of x x that make the denominator zero.
3. Exclude these values from the domain.
4. State the domain of the function.

STEP 3

Identify the denominator of the function f(x)=1x+3 f(x) = \frac{1}{x+3} .
The denominator is x+3 x + 3 .

STEP 4

Determine the values of x x that make the denominator zero by solving the equation:
x+3=0 x + 3 = 0

STEP 5

Solve the equation x+3=0 x + 3 = 0 for x x :
x=3 x = -3
This is the value of x x that makes the denominator zero.

STEP 6

Exclude the value x=3 x = -3 from the domain of the function, as the function is undefined at this point.

STEP 7

State the domain of the function. Since the function is undefined at x=3 x = -3 , the domain is all real numbers except x=3 x = -3 .
In interval notation, the domain is:
(,3)(3,) (-\infty, -3) \cup (-3, \infty)
The domain of the function f(x)=1x+3 f(x) = \frac{1}{x+3} is (,3)(3,) \boxed{(-\infty, -3) \cup (-3, \infty)} .

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