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QuestionFind the mass of water formed when 20.05 g20.05 \, \text{g} sugar reacts with 18.50 g18.50 \, \text{g} oxygen and produces 14.89 g14.89 \, \text{g} CO₂.

Studdy Solution

STEP 1

Assumptions1. The mass of sugar reacting is 20.05 g20.05 \, \text{g} . The mass of oxygen reacting is 18.50 g18.50 \, \text{g}
3. The mass of carbon dioxide formed is 14.89 g14.89 \, \text{g}
4. The balanced chemical equation for the reaction is CxHy+O→CO+HC_xH_y + O \rightarrow CO + H, where xx and yy are some integers5. The law of conservation of mass applies, meaning the total mass of the reactants equals the total mass of the products

STEP 2

First, we need to calculate the total mass of the reactants. This is the sum of the mass of sugar and the mass of oxygen.
Total mass of reactants=Mass of sugar+Mass of oxygen\text{Total mass of reactants} = \text{Mass of sugar} + \text{Mass of oxygen}

STEP 3

Now, plug in the given values for the mass of sugar and the mass of oxygen to calculate the total mass of the reactants.
Total mass of reactants=20.05 g+18.50 g\text{Total mass of reactants} =20.05 \, \text{g} +18.50 \, \text{g}

STEP 4

Calculate the total mass of the reactants.
Total mass of reactants=20.05 g+18.50 g=38.55 g\text{Total mass of reactants} =20.05 \, \text{g} +18.50 \, \text{g} =38.55 \, \text{g}

STEP 5

Next, we need to calculate the total mass of the products. This is the sum of the mass of carbon dioxide and the mass of water. However, we don't know the mass of water yet, so we'll call it WW.
Total mass of products=Mass of carbon dioxide+W\text{Total mass of products} = \text{Mass of carbon dioxide} + W

STEP 6

Plug in the given value for the mass of carbon dioxide.
Total mass of products=14.89 g+W\text{Total mass of products} =14.89 \, \text{g} + W

STEP 7

Now, we can use the law of conservation of mass to set the total mass of the reactants equal to the total mass of the products and solve for WW.
Total mass of reactants=Total mass of products\text{Total mass of reactants} = \text{Total mass of products}38.55 g=14.89 g+W38.55 \, \text{g} =14.89 \, \text{g} + W

STEP 8

Rearrange the equation to solve for WW.
W=38.55 g−14.89 gW =38.55 \, \text{g} -14.89 \, \text{g}

STEP 9

Calculate the mass of water.
W=38.55 g−14.89 g=23.66 gW =38.55 \, \text{g} -14.89 \, \text{g} =23.66 \, \text{g}The mass of water formed in the reaction is 23.66 g23.66 \, \text{g}.

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