Question23.45 Give systematic names for the following formulas: (a) $[Ni(H_2O)_6]Cl_2$ (b) $[Cr(en)_3](ClO_4)_3$ (c) $K_4[Mn(CN)_6]$
Answer (a) hexaaquanickel(II) chloride (b) tris(ethylenediamine) chromium(III) perchlorate (c) potassium
23.46 Give systematic names for the following formulas: (c) $K_2[CuCl_4]$
23.47 What are the charge and coordination number of the central metal ion(s) in each compound in Problem 23.45?

Studdy Solution

STEP 1

What is this asking? We need to name some complex metal compounds, figure out the charge on the metal, and find how many things are attached to it. Watch out! Don't forget those Roman numerals for the metal's charge, and remember the special names for ligands like water and ethylenediamine.

STEP 2

1. Name the Compounds
2. Find Charges and Coordination Numbers

STEP 3

Let's start with $[Ni(H_2O)_6]Cl_2$ .
We've got six water molecules attached to the nickel, and water is called "aqua" as a ligand.
Six is "hexa," so that's hexaaquanickel.
Now, we need the charge on the nickel.
Two chloride ions, each with a $-1$ charge, are balancing it out, so the nickel must have a $+2$ charge.
We write that as (II).
Finally, the counterion is chloride, so the full name is hexaaquanickel(II) chloride.

STEP 4

Next up: $[Cr(en)_3](ClO_4)_3$ . "en" is shorthand for ethylenediamine, and there are three of them, so we use "tris" to get tris(ethylenediamine)chromium.
Three perchlorate ions, each with a $-1$ charge, balance the charge, meaning the chromium has a $+3$ charge, giving us chromium(III).
Putting it all together: tris(ethylenediamine)chromium(III) perchlorate.

STEP 5

Last one for naming: $K_4[Mn(CN)_6]$ .
We have four potassium ions, each with a $+1$ charge, so the complex ion must have a $-4$ charge.
Inside the brackets, six cyanide ions, each with a $-1$ charge, add up to $-6$ .
To get to $-4$ overall, the manganese must have a $+2$ charge.
Cyanide is called "cyano" as a ligand, and six is "hexa," so we have hexacyanomanganese(II).
The counterion is potassium, so the full name is potassium hexacyanomanganese(II).

STEP 6

Let's revisit $[Ni(H_2O)_6]Cl_2$ .
The nickel has a $+2$ charge (we figured that out when naming it).
The coordination number is the number of things attached to the metal, which is six water molecules, so the coordination number is six.

STEP 7

For $[Cr(en)_3](ClO_4)_3$ , the chromium has a $+3$ charge.
Each ethylenediamine molecule attaches at two points, but we still count it as one ligand.
Since there are three ethylenediamine molecules attached, the coordination number is six.

STEP 8

Finally, in $K_4[Mn(CN)_6]$ , the manganese has a $+2$ charge.
Six cyanide ions are attached, so the coordination number is six.

STEP 9

(a) $[Ni(H_2O)_6]Cl_2$ : hexaaquanickel(II) chloride, Charge: $+2$ , Coordination Number: $6$
(b) $[Cr(en)_3](ClO_4)_3$ : tris(ethylenediamine)chromium(III) perchlorate, Charge: $+3$ , Coordination Number: $6$
(c) $K_4[Mn(CN)_6]$ : potassium hexacyanomanganese(II), Charge: $+2$ , Coordination Number: $6$

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Studdy Solution

STEP 1

What is this asking? We need to name some complex metal compounds, figure out the charge on the metal, and find how many things are attached to it. Watch out! Don't forget those Roman numerals for the metal's charge, and remember the special names for ligands like water and ethylenediamine.

STEP 2

1. Name the Compounds
2. Find Charges and Coordination Numbers

STEP 3

STEP 4

STEP 5

STEP 6

Let's revisit $[Ni(H_2O)_6]Cl_2$ .
The nickel has a $+2$ charge (we figured that out when naming it).
The coordination number is the number of things attached to the metal, which is six water molecules, so the coordination number is six.

STEP 7

For $[Cr(en)_3](ClO_4)_3$ , the chromium has a $+3$ charge.
Each ethylenediamine molecule attaches at two points, but we still count it as one ligand.
Since there are three ethylenediamine molecules attached, the coordination number is six.

STEP 8

Finally, in $K_4[Mn(CN)_6]$ , the manganese has a $+2$ charge.
Six cyanide ions are attached, so the coordination number is six.

STEP 9

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Studdy Solution

STEP 1

What is this asking? We need to name some complex metal compounds, figure out the charge on the metal, and find how many things are attached to it. Watch out! Don't forget those Roman numerals for the metal's charge, and remember the special names for ligands like water and ethylenediamine.

STEP 2

1. Name the Compounds2. Find Charges and Coordination Numbers

STEP 3

STEP 4

STEP 5

STEP 6

Let's **revisit** [Ni(H2O)6]Cl2[Ni(H_2O)_6]Cl_2[Ni(H2​O)6​]Cl2​.The nickel has a +2+2+2 charge (we figured that out when naming it).The **coordination number** is the number of things attached to the metal, which is six water molecules, so the coordination number is **six**.

STEP 7

For [Cr(en)3](ClO4)3[Cr(en)_3](ClO_4)_3[Cr(en)3​](ClO4​)3​, the chromium has a +3+3+3 charge.Each ethylenediamine molecule attaches at two points, but we still count it as one ligand.Since there are three ethylenediamine molecules attached, the coordination number is **six**.

STEP 8

Finally, in K4[Mn(CN)6]K_4[Mn(CN)_6]K4​[Mn(CN)6​], the manganese has a +2+2+2 charge.Six cyanide ions are attached, so the coordination number is **six**.

STEP 9

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Start learning now

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1. Name the Compounds
2. Find Charges and Coordination Numbers

Let's revisit $[Ni(H_2O)_6]Cl_2$ .
The nickel has a $+2$ charge (we figured that out when naming it).
The coordination number is the number of things attached to the metal, which is six water molecules, so the coordination number is six.

For $[Cr(en)_3](ClO_4)_3$ , the chromium has a $+3$ charge.
Each ethylenediamine molecule attaches at two points, but we still count it as one ligand.
Since there are three ethylenediamine molecules attached, the coordination number is six.

Finally, in $K_4[Mn(CN)_6]$ , the manganese has a $+2$ charge.
Six cyanide ions are attached, so the coordination number is six.