Question24. The drama club sold all the tickets for its annual production in three days. The club sold 143 tickets the first day and 295 tickets the second day. If the drama club sold 826 tickets, how many tickets were sold on the third day of sales? Solve the equation $438+t=826$ for the number of tickets, $t$ , sold on the third day of ticket sales.

Studdy Solution

STEP 1

1. The drama club sold a total of 826 tickets.
2. 143 tickets were sold on the first day.
3. 295 tickets were sold on the second day.
4. We need to find the number of tickets sold on the third day.
5. The equation to solve is $438 + t = 826$ .

STEP 2

1. Understand the problem and set up the equation.
2. Solve the equation for $t$ .

STEP 3

Understand the problem and set up the equation.
The total number of tickets sold over three days is 826. The tickets sold on the first and second days are 143 and 295, respectively. The sum of tickets sold on the first and second days is:
$143 + 295 = 438$
This means the equation representing the total tickets sold is:
$438 + t = 826$

STEP 4

Solve the equation for $t$ .
Subtract 438 from both sides of the equation to isolate $t$ :
$438 + t - 438 = 826 - 438$
$t = 388$
The number of tickets sold on the third day is:
$\boxed{388}$

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