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PROBLEM

2.6×105 kg moldL=gmolL2.6 \times 10^{-5} \frac{\mathrm{~kg}}{\mathrm{~mol} \cdot \mathrm{dL}}=\square \frac{\mathrm{g}}{\mathrm{mol} \cdot \mathrm{L}}

STEP 1

1. We need to convert units from kg\mathrm{kg} to g\mathrm{g}.
2. We need to convert units from dL\mathrm{dL} to L\mathrm{L}.
3. The conversion factors are 1kg=1000g1 \, \mathrm{kg} = 1000 \, \mathrm{g} and 1L=10dL1 \, \mathrm{L} = 10 \, \mathrm{dL}.

STEP 2

1. Convert kg\mathrm{kg} to g\mathrm{g}.
2. Convert dL\mathrm{dL} to L\mathrm{L}.
3. Combine the conversions to find the final result.

STEP 3

Convert the mass unit from kg\mathrm{kg} to g\mathrm{g}.
\[
2.6 \times 10^{-5} \, \frac{\mathrm{kg}}{\mathrm{mol} \cdot \mathrm{dL}} \times \frac{1000 \, \mathrm{g}}{1 \, \mathrm{kg}} = 2.6 \times 10^{-2} \, \frac{\mathrm{g}}{\mathrm{mol} \cdot \mathrm{dL}}$$

STEP 4

Convert the volume unit from dL\mathrm{dL} to L\mathrm{L}.
\[
2.6 \times 10^{-2} \, \frac{\mathrm{g}}{\mathrm{mol} \cdot \mathrm{dL}} \times \frac{1 \, \mathrm{L}}{10 \, \mathrm{dL}} = 2.6 \times 10^{-3} \, \frac{\mathrm{g}}{\mathrm{mol} \cdot \mathrm{L}}$$

SOLUTION

Combine the conversions to find the final result.
The final result is:
2.6×103gmolL\boxed{2.6 \times 10^{-3} \, \frac{\mathrm{g}}{\mathrm{mol} \cdot \mathrm{L}}}

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