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QuestionWhat is the probability that a randomly assigned two-digit uniform number (10-99) ends in 0? Options: (A) 9100\frac{9}{100} (B) 110\frac{1}{10} (C) 1099\frac{10}{99} (D) 19\frac{1}{9}

Studdy Solution

STEP 1

Assumptions1. The numbers on the uniform range from10 to99, inclusive. . The numbers are two-digit numbers.
3. The numbers are randomly assigned.

STEP 2

First, we need to find the total number of possible outcomes. Since the numbers range from10 to99, there are90 possible outcomes.
Total outcomes=99−10+1=90Total\, outcomes =99 -10 +1 =90

STEP 3

Next, we need to find the number of favorable outcomes. A favorable outcome is a number that ends in0. Since we are dealing with two-digit numbers, there are9 such numbers (10,20, ...,90).
avorable outcomes=9avorable\, outcomes =9

STEP 4

The probability of an event is calculated by dividing the number of favorable outcomes by the total number of outcomes.
Probability=avorable outcomesTotal outcomesProbability = \frac{avorable\, outcomes}{Total\, outcomes}

STEP 5

Now, plug in the values for the favorable outcomes and total outcomes to calculate the probability.
Probability=990Probability = \frac{9}{90}

STEP 6

implify the fraction to get the final probability.
Probability=990=110Probability = \frac{9}{90} = \frac{1}{10}So, the probability that the number on the uniform will end in0 is 110\frac{1}{10}.

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