Math

QuestionCalculate the value of 3+[8÷(3(11))]3+[8 \div(3-(1 \cdot 1))].

Studdy Solution

STEP 1

Assumptions1. We will follow the order of operations, also known as BIDMAS or PEMAS, which stands for Brackets, Indices (or Exponents), Division and Multiplication (from left to right), Addition and Subtraction (from left to right).

STEP 2

First, we need to solve the operation inside the brackets. According to the order of operations, we should first perform multiplication before subtraction.
[8÷((11))]-[8 \div(-(1 \cdot1))]

STEP 3

Now, plug in the given values for the multiplication operation inside the brackets.
3[8÷(31)]3-[8 \div(3-1)]

STEP 4

Next, we need to perform the subtraction operation inside the brackets.
3[8÷2]3-[8 \div2]

STEP 5

Now, we perform the division operation.
3[4]3-[4]

STEP 6

Finally, we perform the subtraction operation.
343-4

STEP 7

Calculate the final result.
1-1So, 3+[÷(3(11))]=13+[ \div(3-(1 \cdot1))] = -1.

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